0=5j^2-20

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Solution for 0=5j^2-20 equation:


Simplifying
0 = 5j2 + -20

Reorder the terms:
0 = -20 + 5j2

Solving
0 = -20 + 5j2

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Add '-5j2' to each side of the equation.
0 + -5j2 = -20 + 5j2 + -5j2
Remove the zero:
-5j2 = -20 + 5j2 + -5j2

Combine like terms: 5j2 + -5j2 = 0
-5j2 = -20 + 0
-5j2 = -20

Divide each side by '-5'.
j2 = 4

Simplifying
j2 = 4

Take the square root of each side:
j = {-2, 2}

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